:confused: Hey 50 mg of test how much in cc
G G-MAN New member Newbies Joined Dec 10, 2006 Messages 6 Jan 16, 2007 #1 Hey 50 mg of test how much in cc Last edited: Jan 16, 2007
Z Zuke New member Registered Joined Jan 26, 2006 Messages 413 Jan 16, 2007 #2 100iu = 1cc. You could have just looked this up. Your post makes no sense.
G G-MAN New member Newbies Joined Dec 10, 2006 Messages 6 Jan 16, 2007 #3 100mg/ml of test I was told to take 50mg a day looking for a converson chart to cc how many mg in a cc ?
100mg/ml of test I was told to take 50mg a day looking for a converson chart to cc how many mg in a cc ?
norm1220 NPC Judge JUDGES Joined Dec 2, 2005 Messages 836 Jan 16, 2007 #4 100mg/ml means that for each milliter(which is marked as a cubic centimeter or cc on a syringe) you will get 100mg of test. So now let's do the math. 50 is what fraction of 100? Yep, it is 1/2 So if there are 100mg of test in 1 cc, how many cc's would it take to get 50mg of test? I'll give you a hint - divide one in half. YES....1/2cc will contain 50mg of test! Next week we will cover using inverse ratios to determine the specific gravity of a compound.
100mg/ml means that for each milliter(which is marked as a cubic centimeter or cc on a syringe) you will get 100mg of test. So now let's do the math. 50 is what fraction of 100? Yep, it is 1/2 So if there are 100mg of test in 1 cc, how many cc's would it take to get 50mg of test? I'll give you a hint - divide one in half. YES....1/2cc will contain 50mg of test! Next week we will cover using inverse ratios to determine the specific gravity of a compound.
G G-MAN New member Newbies Joined Dec 10, 2006 Messages 6 Jan 16, 2007 #5 Yea blond, moment thank you. I got the ratio of weight of a given volume of material to the weight of an equal volume of water. The similarly the impetus of each will be in the inverse compound ratio of the ratios. Thanks class over
Yea blond, moment thank you. I got the ratio of weight of a given volume of material to the weight of an equal volume of water. The similarly the impetus of each will be in the inverse compound ratio of the ratios. Thanks class over